I can’t say that I was ever a particular fan of Bob Dylan’s music. I enjoyed it, but not to the extent that many others have. It is interesting to see the insight that led to the construction of his music. Does reaffirm the thought that one of the most important things in making a piece of art is to know your subject backwards and forwards before you try to use it.

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to everybody who I met at Folklife this past weekend, I seem to have been wrong, I am uncertain about the presence of the usual Art Shuttle, though I will likely be in studio for a fair chunk of the day, and the counterbalance brewery will be open around the corner.

That said, do feel free to come by for a visit after 6 pm as I will definitely be here from 6-9 as promised, possibly later…

See you then!

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This being the first attempt I am sticking to a fairly traditional interpretation of the corinthian capital. Here I have roughed out the acanthus leaves of the first two tiers of the standard pattern.

One problem I have encountered so far is making sure the leaves are rising straight up. given a certain right handed bias, they have all tended to sway slightly to the left… will be breaking out the plumb bob (or equivalent) for the next one…

Continuing from #step 1

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at $15 a pop for three hours of drawing with a mixture of pose lengths in a very pleasant studio setting in Georgetown, Praxis Arts is one of the more enjoyable places to draw

Still need more practes

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Turns out there’s a relatively simple geometric recipe to create such a template. here it is for your convenience.

to explain, for a truncated cone:

- draw a vertical line
- at the bottom of the vertical line, draw a line perpendicular to the first one, centered on the vertical line from step one. this line should be the diameter of the wide end of the cone. you should now have an upside down ‘T’
- measure up the vertical line the height of the desired truncated cone
- at the point found in step 3, draw another line perpendicular to the vertical line, this time the length should be the diameter of the small end of the truncated cone.
- connect the ends of the horizontal lines and extend the resulting line until it crosses the vertical line. (depending on your desired cone, this could be at some considerable distance…
- with a compass, make two circles using the point where the vertical line and the line from step 5 cross as the center of the circle. the radius of these two circles should be the points where the step 5 line crosses the two horizontal lines.
- now you need to figure out the length of the perimeter of one of the ends of the truncated cone. using the horizontal line from step 2 is easiest. the formula is π times the diameter. (chances are that the scale is small enough that using 22/7 is probably not a bad idea)
- with a flexible tape measure, measure out along the circle line the distance calculated in step 7
- 9 draw a straight line between the point found in step 8 and the point found in step 5

at this point you’re done. as you can see in the diagram above, the resulting grey area can be cut out and developed into a cone shape.

if requested, I can turn this into a series of visual steps…

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There will be some newer examples of the mica white planters, this time with liner pots.

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I’ve been going to a local drink and draw where an 18″x24″ pad and board might be a little inconvenient. I recommend the location, the Conservatory is a pleasant place to get a glass of wine and draw a (costumed) model. The following are some pencil/charcoal sketches from a couple of sessions.

May end up on the king5 Friday broadcast one of these days, as they were shooting a segment during the latter session.

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These are the basis for some experiments in classical architecture…

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A question came up recently about how to adjust the size of a vessel so that you get a certain amount more volume. So given a cup of a certain radius and a certain height, how do you adjust one or the other to, say, double the volume? Height is easy, if you want to double the volume, double the height. Radius on the other hand, is a bit trickier.

So the formula of a cylinder is Volume=height × π × (radius²) or V=hπr². easy to see that if you change ‘h’ you get a linear relationship between height and volume.

Radius though, that requires some extra math. First step is to set up an equivalency.

hπ(yr)² = xhπr²

There is some value ‘y’ that we can multiply the radius by that would be equivalent to multiplying the height by ‘x’ so lets isolate ‘y’ .

Divide both sides by ‘h’ and ‘π’ and they cancel out.

(yr)² = xr²

Square root both sides to get

yr = √(xr²)

Now divide both sides by r:

y = √(xr²)/r

So if you want double the volume, you would substitute 2 for ‘x’ and get an answer of around 1.4. You then multiply your original radius (or diameter) by 1.4 and your cylinder will have twice the volume. Since this is a quadratic equation, you can then see that if you want to quadruple your volume, the radius multiplier is 2. if you want to increase your volume 9-fold, multiply radius by 3, etc. etc…

If you are working with a mac, the handy graphing calculator makes this very easy to visualize.

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